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dZt = aZt dWt + bZt dt.

Note that this equation is linear in Zt , and it turns out that linear equations are almost
the only ones that have an explicit solution. In this case we can write down the explicit
solution and then verify that it satisп¬Ѓes the SDE. The uniqueness result above (Theorem
15.1) shows that we have in fact found the solution.
Let
2
Zt = Z0 eaWt в€’a t/2+bt .

We will verify that this is correct by using ItoвЂ™s formula. Let Xt = aWt в€’ a2 t/2 + bt. Then
Xt is a semimartingale with martingale part aWt and X t = a2 t. Zt = eXt . By ItoвЂ™s
formula with f (x) = ex ,
t t
Xs
eXs a2 ds
1
Zt = Z0 + e dXs + 2
0 0
t t2 t
a
aZs dWs в€’
= Z0 + Zs ds + bZs ds
2
0 0 0
t
a2 Zs ds
1
+ 2
0
t t
= aZs dWs + bZs ds.
0 0

This is the integrated form of the equation we wanted to solve.
There is a connection between SDEs and partial diп¬Ђerential equations. Let f be a
C 2 function. If we apply ItoвЂ™s formula,
t t
1
f (Xt ) = f (X0 ) + f (Xs )dXs + f (Xs )d X s .
2
0 0

t
Пѓ(Xs )2 ds. If we substitute for dXs and d X s , we obtain
From (15.2) we know X =
t 0

t t
f (Xt ) = f (X0 ) + f (Xs )dWs + Вµ(Xs )ds
0 0
t
f (Xs )Пѓ(Xs )2 ds
1
+ 2
0
t t
Lf (Xs )ds,
= f (X0 ) + f (Xs )dWs +
0 0

where we write
Lf (x) = 2 Пѓ(x)2 f (x) + Вµ(x)f (x).
1

71
L is an example of a diп¬Ђerential operator. Since the stochastic integral with respect to a
Brownian motion is a martingale, we see from the above that
t
f (Xt ) в€’ f (X0 ) в€’ Lf (Xs )ds
0

is a martingale. This fact can be exploited to derive results about PDEs from SDEs and
vice versa.

Note 1. Let us illustrate the uniqueness part, and for simplicity, assume b is identically 0 and
Пѓ is bounded.

Proof of uniqueness. If X and Y are two solutions,
t
Xt в€’ Yt = [Пѓ(Xs ) в€’ Пѓ(Ys )]dWs .
0

So
t t
2 2
E |Xs в€’ Ys |2 ds,
E |Xt в€’ Yt | = E |Пѓ(Xs ) в€’ Пѓ(Ys )| ds в‰¤ c
0 0

using the Lipschitz hypothesis on Пѓ. If we let g(t) = E |Xt в€’ Yt |2 , we have
t
g(t) в‰¤ c g(s) ds.
0

t
2
(Пѓ(Xs ))2 ds в‰¤ ct and similarly for E Yt2 , so
Since we are assuming Пѓ is bounded, E Xt = E 0
g(t) в‰¤ ct. Then
t s
g(t) в‰¤ c c g(r) dr ds.
0 0

Iteration implies
g(t) в‰¤ Atn /n!

for each n, which implies g must be 0.

72
16. Continuous time п¬Ѓnancial models.
The most common model by far in п¬Ѓnance is one where the security price is based
on a Brownian motion. One does not want to say the price is some multiple of Brownian
motion for two reasons. First, of all, a Brownian motion can become negative, which
doesnвЂ™t make sense for stock prices. Second, if one invests \$1,000 in a stock selling for \$1
and it goes up to \$2, one has the same proп¬Ѓt, namely, \$1,000, as if one invests \$1,000 in a
stock selling for \$100 and it goes up to \$200. It is the proportional increase one wants.
Therefore one sets в€†St /St to be the quantity related to a Brownian motion. Diп¬Ђer-
ent stocks have diп¬Ђerent volatilities Пѓ (consider a high-tech stock versus a pharmaceutical).
In addition, one expects a mean rate of return Вµ on oneвЂ™s investment that is positive (oth-
erwise, why not just put the money in the bank?). In fact, one expects the mean rate
of return to be higher than the risk-free interest rate r because one expects something in
return for undertaking risk.
So the model that is used is to let the stock price be modeled by the SDE

dSt /St = ПѓdWt + Вµdt,

or what looks better,
dSt = ПѓSt dWt + ВµSt dt. (16.1)

Fortunately this SDE is one of those that can be solved explicitly, and in fact we
gave the solution in Section 15.

Proposition 16.1. The solution to (16.1) is given by
2
St = S0 eПѓWt +(Вµв€’(Пѓ /2)t)
. (16.2)

Proof. Using Theorem 15.1 there will only be one solution, so we need to verify that St
as given in (16.2) satisп¬Ѓes (16.1). We already did this, but it is important enough that we
will do it again. Let us п¬Ѓrst assume S0 = 1. Let Xt = ПѓWt + (Вµ в€’ (Пѓ 2 /2)t, let f (x) = ex ,
and apply ItoвЂ™s formula. We obtain
t t
Xt X0 Xs
eXs d X
1
St = e =e + e dXs + s
2
0 0
t t
Ss (Вµ в€’ 2 Пѓ 2 )ds
1
=1+ Ss ПѓdWs +
0 0
t
Ss Пѓ 2 ds
1
+ 2
0
t t
=1+ Ss ПѓdWs + Ss Вµds,
0 0

73
which is (16.1). If S0 = 0, just multiply both sides by S0 .

Suppose for the moment that the interest rate r is 0. If one purchases в€†0 shares
(possibly a negative number) at time t0 , then changes the investment to в€†1 shares at time
t1 , then changes the investment to в€†2 at time t2 , etc., then oneвЂ™s wealth at time t will be
Xt0 + в€†0 (St1 в€’ St0 ) + в€†1 (St2 в€’ St1 ) + В· В· В· + в€†i (Sti+1 в€’ Sti ). (16.3)
To see this, at time t0 one has the original wealth Xt0 . One buys в€†0 shares and the cost
is в€†0 St0 . At time t1 one sells the в€†0 shares for the price of St1 per share, and so oneвЂ™s
wealth is now Xt0 + в€†0 (St1 в€’ St0 ). One now pays в€†1 St1 for в€†1 shares at time t1 and
continues. The right hand side of (16.3) is the same as
t
Xt0 + в€†(s)dSs ,
t0
where we have t в‰Ґ ti+1 and в€†(s) = в€†i for ti в‰¤ s < ti+1 . In other words, our wealth is
given by a stochastic integral with respect to the stock price. The requirement that the
integrand of a stochastic integral be adapted is very natural: we cannot base the number
of shares we own at time s on information that will not be available until the future.
How should we modify this when the interest rate r is not zero? Let Pt be the
present value of the stock price. So
Pt = eв€’rt St .
Note that P0 = S0 . When we hold в€†i shares of stock from ti to ti+1 , our proп¬Ѓt in present
days dollars will be
в€†i (Pti+1 в€’ Pti ).
The formula for our wealth then becomes
t
Xt0 + в€†(s)dPs .
t0
By ItoвЂ™s product formula,
dPt = eв€’rt dSt в€’ reв€’rt St dt
= eв€’rt ПѓSt dWt + eв€’rt ВµSt dt в€’ reв€’rt St dt
= ПѓPt dWt + (Вµ в€’ r)Pt dt.
Similarly to (16.2), the solution to this SDE is
2
Pt = P0 eПѓWt +(Вµв€’rв€’Пѓ /2)t
. (16.4)
The continuous time model of п¬Ѓnance is that the security price is given by (16.1)
(often called geometric Brownian motion), that there are no transaction costs, but one can
trade as many shares as one wants and vary the amount held in a continuous fashion. This
clearly is not the way the market actually works, for example, stock prices are discrete,
but this model has proved to be a very good one.

74
17. Markov properties of Brownian motion.
Let Wt be a Brownian motion. Because Wt+r в€’ Wt is independent of Пѓ(Ws : s в‰¤ t),
then knowing the path of W up to time s gives no help in predicting Wt+r в€’ Wt . In
particular, if we want to predict Wt+r and we know Wt , then knowing the path up to time
t gives no additional advantage in predicting Wt+r . Phrased another way, this says that
to predict the future, we only need to know where we are and not how we got there.
LetвЂ™s try to give a more precise description of this property, which is known as the
Markov property.
Fix r and let Zt = Wt+r в€’ Wr . Clearly the map t в†’ Zt is continuous since the
same is true for W . Since Zt в€’ Zs = Wt+r в€’ Ws+r , then the distribution of Zt в€’ Zs is
normal with mean zero and variance (t + r) в€’ (s + r). One can also check the other parts
of the deп¬Ѓnition to show that Zt is also a Brownian motion.
Recall that a stopping time in the continuous framework is a r.v. T taking values
in [0, в€ћ) such that (T в‰¤ t) в€€ Ft for all t. To make a satisfactory theory, we need that the
Ft be right continuous (see Section 10), but this is fairly technical and we will ignore it.
If T is a stopping time, FT is the collection of events A such that A в€© (T > t) в€€ Ft
for all t.
Let us try to provide some motivation for this deп¬Ѓnition of FT . It will be simpler to
consider the discrete time case. The analogue of FT in the discrete case is the following:
if N is a stopping time, let

FN = {A : A в€© (N в‰¤ k) в€€ Fk for all k}.

If Xk is a sequence that is adapted to the Пѓ-п¬Ѓelds Fk , that is, Xk is Fk measurable when
k = 0, 1, 2, . . ., then knowing which events in Fk have occurred allows us to calculate Xk
for each k. So a reasonable deп¬Ѓnition of FN should allow us to calculate XN whenever
we know which events in FN have occurred or not. Or phrased another way, we want XN
to be FN measurable. Where did the sequence Xk come from? It could be any adapted
sequence. Therefore one deп¬Ѓnition of the Пѓ-п¬Ѓeld of events occurring before time N might
be:
Consider the collection of random variables XN where Xk is a sequence adapted
to Fk . Let GN be the smallest Пѓ-п¬Ѓeld with respect to which each of these random
variables XN is measurable.
In other words, we want GN to be the Пѓ-п¬Ѓeld generated by the collection of random
variables XN for all sequences Xk that are adapted to Fk .
We show in Note 1 that FN = GN . The Пѓ-п¬Ѓeld FN is just a bit easier to work with.
Now we proceed to the strong Markov property for Brownian motion, the proof of
which is given in Note 2.

75
Proposition 17.1. If Xt is a Brownian motion and T is a bounded stopping time, then
XT +t в€’ XT is a mean 0 variance t random variable and is independent of FT .
This proposition says: if you want to predict XT +t , you could do it knowing all of
FT or just knowing XT . Since XT +t в€’ XT is independent of FT , the extra information
given in FT does you no good at all.
We need a way of expressing the Markov and strong Markov properties that will
generalize to other processes.
Let Wt be a Brownian motion. Consider the process Wtx = x + Wt , which is known
as Brownian motion started at x. Deп¬Ѓne в„¦ to be set of continuous functions on [0, в€ћ), let
Xt (П‰) = П‰(t), and let the Пѓ-п¬Ѓeld be the one generated by the Xt . Deп¬Ѓne Px on (в„¦ , F ) by

Px (Xt1 в€€ A1 , . . . , Xtn в€€ An ) = P(Wtx в€€ A1 , . . . , Wtx в€€ An ).
1 n

What we have done is gone from one probability space в„¦ with many processes Wtx to one
process Xt with many probability measures Px .
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